50x^2+350x-6000=0

Solution for 50x^2+350x-6000=0 equation:

50x^2+350x-6000=0

a = 50; b = 350; c = -6000;
Δ = b2-4ac
Δ = 3502-4·50·(-6000)
Δ = 1322500
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1322500}=1150$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(350)-1150}{2*50}=\frac{-1500}{100}
=-15
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(350)+1150}{2*50}=\frac{800}{100}
=8
$